#### Determine the voltage V1 for the network shown in figure

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#### The equivalent capacitance of circuit is

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#### How long will a 9V battery with an ampere hour rating of 520 mAH will provide the current of 20mA

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Life = 520𝑚𝐴ℎ/20𝑚𝐴 = 26h

#### Find equivalent resistance between A and B

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#### Find equivalent resistance between the ends

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#### There are ‘n’ number of wires of resistance ‘R’ , what will be the ratio of maximum to minimum resistance

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#### Determine the current of the following network shown in figure

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#### Determine the input impedance of the RLC series network

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#### How much energy in kilo-watt hour is required to light a bulb of a 60W continuously for one year

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#### When AC flows through a capacitor then the current

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#### Find equivalent resistance between A and B

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#### Calculate the equivalent inductance of the network

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#### Super-position theorem is applicable to the

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#### Unit of luminous intensity is

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#### The internal resistance of an ideal voltage source

Please select 2 correct answers

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#### Electrical energy is measured in

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#### Electric field intensity is

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#### All the current in series circuit are

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#### Unit of potential is

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#### SI unit of power is

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#### Find Thevenin’s equivalent resistance and Thevenin’s voltage of circuit if V=10 V

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#### The maximum power delivered to the load when

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#### In a series RLC circuit, setting R=0 will produce

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#### Inductor store energy in

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Aoun AbbasKindly again confirm the answer of following:

Superposition is applicable to both voltage and current but it is not applicable to power because it is only applicable for Linear quantities whereas power is not a linear quantity.

Thank you !

Kamyab EngineerPost authorThank you for the feedback

Rubyplease correct

The internal resistance of an ideal voltage source is Zero

Kamyab EngineerPost authorThank you we will look into that.

Kamyab EngineerPost authorThank you, we will check

Syed Umair Ali ShahMy answer is Rth=10 ohm, Vth=10 V. Please correct me if I am wrong otherwise correct the answer.

Syed Umair Ali ShahSorry I was wrong. Because the voltage drop across the 5 ohm resistor is to be taken as Vth and it turns out to be 5V.

Kamyab EngineerPost authorThank you for your participation